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9x^2-108x+70=0
a = 9; b = -108; c = +70;
Δ = b2-4ac
Δ = -1082-4·9·70
Δ = 9144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9144}=\sqrt{36*254}=\sqrt{36}*\sqrt{254}=6\sqrt{254}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-6\sqrt{254}}{2*9}=\frac{108-6\sqrt{254}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+6\sqrt{254}}{2*9}=\frac{108+6\sqrt{254}}{18} $
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